0.5x^2+3x-8=0

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Solution for 0.5x^2+3x-8=0 equation: 



0.5x^2+3x-8=0

a = 0.5; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·0.5·(-8)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*0.5}=\frac{-8}{1}
=-8
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*0.5}=\frac{2}{1}
=2
$

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